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"""
MLflow-related functions to load models and apply them to pandas-on-Spark dataframes.
"""
from typing import List, Union

from pyspark.sql.types import DataType
import pandas as pd
import numpy as np
from typing import Any

from pyspark.pandas._typing import Label, Dtype
from pyspark.pandas.utils import lazy_property, default_session
from pyspark.pandas.frame import DataFrame
from pyspark.pandas.series import Series, first_series
from pyspark.pandas.typedef import as_spark_type

__all__ = ["PythonModelWrapper", "load_model"]


class PythonModelWrapper:
    """
    A wrapper around MLflow's Python object model.

    This wrapper acts as a predictor on pandas-on-Spark

    """

    def __init__(self, model_uri: str, return_type_hint: Union[str, type, Dtype]):
        self._model_uri = model_uri
        self._return_type_hint = return_type_hint

    @lazy_property
    def _return_type(self) -> DataType:
        hint = self._return_type_hint
        # The logic is simple for now, because it corresponds to the default
        # case: continuous predictions
        # TODO: do something smarter, for example when there is a sklearn.Classifier (it should
        # return an integer or a categorical)
        # We can do the same for pytorch/tensorflow/keras models by looking at the output types.
        # However, this is probably better done in mlflow than here.
        if hint == "infer" or not hint:
            hint = np.float64
        return as_spark_type(hint)

    @lazy_property
    def _model(self) -> Any:
        """
        The return object has to follow the API of mlflow.pyfunc.PythonModel.
        """
        from mlflow import pyfunc

        return pyfunc.load_model(model_uri=self._model_uri)

    @lazy_property
    def _model_udf(self) -> Any:
        from mlflow import pyfunc

        spark = default_session()
        return pyfunc.spark_udf(spark, model_uri=self._model_uri, result_type=self._return_type)

    def __str__(self) -> str:
        return "PythonModelWrapper({})".format(str(self._model))

    def __repr__(self) -> str:
        return "PythonModelWrapper({})".format(repr(self._model))

    def predict(self, data: Union[DataFrame, pd.DataFrame]) -> Union[Series, pd.Series]:
        """
        Returns a prediction on the data.

        If the data is a pandas-on-Spark DataFrame, the return is a pandas-on-Spark Series.

        If the data is a pandas Dataframe, the return is the expected output of the underlying
        pyfunc object (typically a pandas Series or a numpy array).
        """
        if isinstance(data, pd.DataFrame):
            return self._model.predict(data)
        elif isinstance(data, DataFrame):
            return_col = self._model_udf(*data._internal.data_spark_columns)
            # TODO: the columns should be named according to the mlflow spec
            # However, this is only possible with spark >= 3.0
            # s = F.struct(*data.columns)
            # return_col = self._model_udf(s)
            column_labels: List[Label] = [
                (col,) for col in data._internal.spark_frame.select(return_col).columns
            ]
            internal = data._internal.copy(
                column_labels=column_labels, data_spark_columns=[return_col], data_fields=None
            )
            return first_series(DataFrame(internal))
        else:
            raise ValueError("unknown data type: {}".format(type(data).__name__))


def load_model(
    model_uri: str, predict_type: Union[str, type, Dtype] = "infer"
) -> PythonModelWrapper:
    """
    Loads an MLflow model into an wrapper that can be used both for pandas and pandas-on-Spark
    DataFrame.

    Parameters
    ----------
    model_uri : str
        URI pointing to the model. See MLflow documentation for more details.
    predict_type : a python basic type, a numpy basic type, a Spark type or 'infer'.
       This is the return type that is expected when calling the predict function of the model.
       If 'infer' is specified, the wrapper will attempt to determine automatically the return type
       based on the model type.

    Returns
    -------
    PythonModelWrapper
        A wrapper around MLflow PythonModel objects. This wrapper is expected to adhere to the
        interface of mlflow.pyfunc.PythonModel.

    Examples
    --------
    Here is a full example that creates a model with scikit-learn and saves the model with
     MLflow. The model is then loaded as a predictor that can be applied on a pandas-on-Spark
     Dataframe.

    We first initialize our MLflow environment:

    >>> from mlflow.tracking import MlflowClient, set_tracking_uri
    >>> import mlflow.sklearn
    >>> from tempfile import mkdtemp
    >>> d = mkdtemp("pandas_on_spark_mlflow")
    >>> set_tracking_uri("file:%s"%d)
    >>> client = MlflowClient()
    >>> exp_id = mlflow.create_experiment("my_experiment")
    >>> exp = mlflow.set_experiment("my_experiment")

    We aim at learning this numerical function using a simple linear regressor.

    >>> from sklearn.linear_model import LinearRegression
    >>> train = pd.DataFrame({"x1": np.arange(8), "x2": np.arange(8)**2,
    ...                       "y": np.log(2 + np.arange(8))})
    >>> train_x = train[["x1", "x2"]]
    >>> train_y = train[["y"]]
    >>> with mlflow.start_run():
    ...     lr = LinearRegression()
    ...     lr.fit(train_x, train_y)
    ...     mlflow.sklearn.log_model(lr, "model")
    LinearRegression(...)

    Now that our model is logged using MLflow, we load it back and apply it on a pandas-on-Spark
    dataframe:

    >>> from pyspark.pandas.mlflow import load_model
    >>> run_info = client.list_run_infos(exp_id)[-1]
    >>> model = load_model("runs:/{run_id}/model".format(run_id=run_info.run_uuid))
    >>> prediction_df = ps.DataFrame({"x1": [2.0], "x2": [4.0]})
    >>> prediction_df["prediction"] = model.predict(prediction_df)
    >>> prediction_df
        x1   x2  prediction
    0  2.0  4.0    1.355551

    The model also works on pandas DataFrames as expected:

    >>> model.predict(prediction_df[["x1", "x2"]].to_pandas())
    array([[1.35555142]])

    Notes
    -----
    Currently, the model prediction can only be merged back with the existing dataframe.
    Other columns have to be manually joined.
    For example, this code will not work:

    >>> df = ps.DataFrame({"x1": [2.0], "x2": [3.0], "z": [-1]})
    >>> features = df[["x1", "x2"]]
    >>> y = model.predict(features)
    >>> # Works:
    >>> features["y"] = y   # doctest: +SKIP
    >>> # Will fail with a message about dataframes not aligned.
    >>> df["y"] = y   # doctest: +SKIP

    A current workaround is to use the .merge() function, using the feature values
    as merging keys.

    >>> features['y'] = y
    >>> everything = df.merge(features, on=['x1', 'x2'])
    >>> everything
        x1   x2  z         y
    0  2.0  3.0 -1  1.376932
    """
    return PythonModelWrapper(model_uri, predict_type)


def _test() -> None:
    import os
    import doctest
    import sys
    from pyspark.sql import SparkSession
    import pyspark.pandas.mlflow

    os.chdir(os.environ["SPARK_HOME"])

    globs = pyspark.pandas.mlflow.__dict__.copy()
    globs["ps"] = pyspark.pandas
    spark = (
        SparkSession.builder.master("local[4]").appName("pyspark.pandas.mlflow tests").getOrCreate()
    )
    (failure_count, test_count) = doctest.testmod(
        pyspark.pandas.mlflow,
        globs=globs,
        optionflags=doctest.ELLIPSIS | doctest.NORMALIZE_WHITESPACE,
    )
    spark.stop()
    if failure_count:
        sys.exit(-1)


if __name__ == "__main__":
    try:
        import mlflow  # noqa: F401
        import sklearn  # noqa: F401

        _test()
    except ImportError:
        pass
